46th B.P.S.C. (Pre) 2004

$x = a Cos\theta + b Sin\theta$ $y = a Sin\theta - b Cos\theta$ $x^2 + y^2$ is equal to-

a$a^2 - b^2$
b$b^2 - a^2$
c$a^2 + b^2$✓ Correct
d$a^2 + 2ab$

Explanation

$x = a Cos\theta + b Sin\theta$ $x^2 = (a Cos\theta + b Sin\theta)^2$ $y = (a Sin\theta - b Cos\theta)$ $y^2 = (a Sin\theta - b Cos\theta)^2$ $x^2 + y^2 = (a Cos\theta + b Sin\theta)^2 + (a Sin\theta - b Cos\theta)^2$ $= a^2 (Sin^2\theta + Cos^2\theta) + b^2 (sin^2\theta + Cos^2\theta)$ $+ 2ab Cos\thetaSin\theta - 2ab Sin\theta.Cos\theta$ $x^2 + y^2 = a^2 + b^2$

general-mental-ability