Which of the following will have the maximum weight?

Explanation

## Page 34 Molecular weight of sucrose (C₁₂H₂₂O₁₁) = 12 × atomic weight of C + 22 × atomic weight + 11 × atomic weight of O = (12×12) + (22×1) + (11×16) = 342 g/mol Weight of 0.2 mole of sucrose = 342 × 0.2 = 68.4 g Weight of CO₂ = (12×1) + (16×2) = 44 g/mol Weight of 2 moles of CO₂ = 44 × 2 = 88 g Weight of 2 moles of CaCO₃ = 2 × [(1× atomic weight of Ca) + (1× atomic weight of C) + (3× atomic weight of O)] = 2 × (40 + 12 + 3×16) = 200 g Therefore, among the given options, the weight of 2 moles of CaCO₃ is the maximum.