What is the length of the diameter of that circular field whose area is equal to the sum of the area of a circle of radius 8 m and the area of a triangle with area 36πm²?

Explanation

## Page 26 ∵ Area of the circle = $\pi \times 8 \times 8$ = $64\pi$ m.² According to the question Area of the circular field = $64\pi$ m.² + $36\pi$ m.² = $100\pi$ m.² $\pi r^2 = 100 \pi$m.² r = 100 m.² r = 10 m. ∴ Diameter of circular ground = $2 \times 10 \Rightarrow 20$ m.