Two pillars are standing on flat ground, whose height are 6m and 11m. If the distance between their lower ends on the ground is 12 m. then. What will be the distance between their ends?

Explanation

AB and AC are pillars, whose heights are 6m and 11m. CD = CE - ED = 11 - 6 (ED = AB = 6m) = 5m In $\Delta$ ACD AD = 12m ($\therefore$ AD =BE) CD = 5m AC² = AD² + CD² AC = $\sqrt{12^2 + 5^2}$ $\boxed{AC=13m}$ Diagram showing two pillars with heights 6m and 11m, distance 12m, and calculation steps (491) ## Page 40