B.P.S.C. Teacher (9th-10th) 08.12.2023
The value of $\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right).........\left(1-\frac{1}{n}\right)$ is -
a$\frac{n-1}{n}$
b$\frac{1}{n}$✓ Correct
c$\frac{1}{n+1}$
dMore than one of the above
eNone of the above
Explanation
$\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right).........\left(1-\frac{1}{n}\right)$ $= \frac{1}{2} \times \frac{2}{3} \times \frac{3}{4} ........... \frac{n-1}{n} = \frac{1}{n}$
general-mental-ability
