The value of $\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right)\left(1+\frac{1}{4}\right).........\left(1+\frac{1}{120}\right)$ is -

Explanation

$\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right)\left(1+\frac{1}{4}\right).........\left(1+\frac{1}{120}\right)$ $= \frac{3}{2} \times \frac{4}{3} \times \frac{5}{4} \times .......... \times \frac{121}{120}$ $= \frac{121}{2} \Rightarrow 60.5$