B.P.S.C. TRE-3 July, 2024
The lengths of the diagonals of a rhombus are 2a and 2b. Its perimeter is -
a$2\sqrt{a^2 + b^2}$
b4ab
c$4\sqrt{a^2 + b^2}$✓ Correct
dMore than one of the above
eNone of the above
Explanation
A D <table> <tr> <th>\ /</th> </tr> <tr> <td>X</td> </tr> <tr> <td>/ \</td> </tr> </table> B C $\therefore$ Side of the rhombus (BC) = $\sqrt{a^2 + b^2}$ $\because$ Perimeter of the rhombus = 4 × side $\therefore$ Required result = $4\sqrt{a^2 + b^2}$
general-mental-ability