The lengths of the diagonals of a rhombus are 10 cm and 24 cm. Its perimeter is

Explanation

We know that– $d_1^2 + d_2^2 = 4a^2$ (where $a$ = side $d_1$, $d_2$ are diagonals of rhombus) Side of rhombus = $\frac{1}{2} \times \sqrt{(Diagonal_1)^2 + (Diagonal_2)^2}$ = $\frac{1}{2}\sqrt{(10)^2 + (24)^2} = \frac{1}{2}\sqrt{100 + 576}$ = $\frac{1}{2}\sqrt{676} = \frac{1}{2} \times 26 = 13$ cm $\therefore$ Perimeter of rhombus = 4 × side = (4 × 13) cm = 52 cm