In $\Delta$ABC, if AB = 16 cm, BC = 12 cm, and AC = 20 cm, then $\Delta$ABC is-

Explanation

From the Pythagorean theorem in right triangle $\Delta$ A triangle with vertices A, B, C. Side AB is labeled 16. Side BC is labeled 12. Side AC is labeled 20. $(AB)^2 + (BC)^2 = (AC)^2$ $\therefore (16)^2 + (12)^2 = (20)^2$ $256 + 144 = 400$ $400 = 400$ Therefore, the given triangle is a right-angled triangle.