If the roots of equation $x^2 +11x + 50 = 0$ are $\alpha, \beta$ is, then $\frac{\alpha}{\beta} + \frac{\beta}{\alpha}=?$

Explanation

Equation $x^2 +11x + 50 = 0$ $\alpha + \beta = \frac{-11}{1}$ (Sum of roots = $\frac{-b}{a}$) $\alpha.\beta = \frac{50}{1}$ (products of root = $\frac{c}{a}$) $\frac{\alpha}{\beta} + \frac{\beta}{\alpha} = \frac{\alpha^2 + \beta^2}{\alpha\beta}$ $= \frac{(\alpha + \beta)^2 - 2\alpha\beta}{\alpha\beta}$ Putting the value of $\alpha + \beta$ and $\alpha.\beta$ $= \frac{(-11)^2 - 2(50)}{50}$ $= \frac{21}{50} = 0.42$