BPSC (Tre-3) {July}–2024

If the capacity of a cylindrical tank is $1848 m^3$ and the diameter of its base is $14 m$, the depth of the tank is : ($\pi = \frac{22}{7}$)

a$8 m$
b$12 m$✓ Correct
c$16 m$
dMore than one of the above
eNone of the above

Explanation

Given that– Volume of the tank is $1848 m^3$ and diameter of its base is $14 m$ also, we know that– Volume of Cylinder = $\pi r^2 h$ ($\because$ where is the depth of the cylinder) $$ 1848 = \frac{22}{7} \times 7 \times 7 \times h $$ ($\because 2r = 14 \Rightarrow r = 7$) $$ 1848 = 22 \times 7 \times h $$ $$ h = \frac{1848}{22 \times 7} $$ $$ h = 12 meters $$

general-science