A solid piece of iron (49 cm. × 33 cm. × 24 cm.) is in the base of a cuboid with dimensions. It is melted to form a solid sphere. The radius of the sphere is-

Explanation

Let the radius of the sphere be r cm. As per the question, Volume of sphere = Volume of cuboid $$ \frac{4}{3} \times \pi \times r^3 = 49 \times 33 \times 24 $$ $$ \frac{4}{3} \times \frac{22}{7} \times r^3 = 49 \times 33 \times 24 $$ $$ r^3 = \frac{49 \times 33 \times 24 \times 3 \times 7}{4 \times 22} $$ r = 21 cm.