A room is $8$ meters long, $6$ meters wide, and $10$ meters high, then the length of the longest pole that can be place din the room is -

Explanation

Given, the length of the room is $(l) = 8$ meters Width $(b) = 6$ meters Height $(h) = 10$ meters Length of the longest pole that can be placed in the room (diagonal) $$ = \sqrt{l^2 + b^2 + h^2} $$ $$ = \sqrt{8^2 + 6^2 + 10^2} $$ $$ = \sqrt{64 + 36 + 100} $$ $$ = \sqrt{200} $$ $$ = \sqrt{100 \times 2} $$ $$ = 10\sqrt{2} $$